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I am not sure how to place my voltage source after i combine the 2 parallel resistors R1 and R2. Can someone please help me with this?

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Method1 (specific method for voltage divider):
After you simplified the parralel resistors \$R_{23} = R_2 || R_3\$ you got a voltage source with voltage divider formed by \$R_{23}\$ and \$R_1\$.

The Thevenin Equivalent of a voltage source \$V_{src}\$ with voltage divider is a Thevenin source with \$V_{th}=V_{src}\frac{R_{23}}{R_1+R_{23}}\$ and \$R_{th}= R_1 || R_{23}\$

Method2 (general method that works always):
If you don't know this shortcut above: do what you should have learned in the lessons:

  • find open circuit voltage \$V_{oc}\$ between a and b
  • find short circuit current \$I_{sc}\$ between a and b
  • use both results to derive \$V_{th}=V_{oc}\$ and \$R_{th}=\frac{V_{oc}}{I_{sc}}\$.
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First, r2//r3 so you find the equivalent resistance Req1. Then you see that R1 and Req1 are in series so you find the equivalent resistance between r1 an Req1 and i think it's good. you have your equivalent schema.

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  • \$\begingroup\$ The OP asked about using Thevenin. \$\endgroup\$ – Chu May 17 '17 at 14:18
  • \$\begingroup\$ i should have said it was the beginning of method to find equivalent schema. After you just had to as @curd said. Sorry i wasn't explicit. \$\endgroup\$ – Dipo May 17 '17 at 14:39

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