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There are projects like this one over here: Underground Cable Fault Distance Finder, which checks if a given line is short-ciruited with any of the other lines. The location of the fault is also calculated by a voltage divider method. I want to know if there is a method to detect an open circuit fault on the line, using just a single wire, similar to the resistance voltage divider. This should mimic a real implementation.

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  • \$\begingroup\$ Since you want to detect an open, no current can flow making voltage detection impossible. It is however possible to detect an open (and shorts as well) using a different method. This method sends a pulse into the wire and depending on how that pulse is reflected, short/open and the distance to it can be measured. \$\endgroup\$ – Bimpelrekkie May 31 '17 at 15:09
  • \$\begingroup\$ Okay. Can you please elaborate? What do you mean by reflect? \$\endgroup\$ – sixter May 31 '17 at 15:11
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    \$\begingroup\$ I'm refering to a device like this: amazon.com/Fluke-Networks-DTX-1800-Cable-Analyzer/dp/B00ATQWN5A They're not cheap ! Reflect means: a pulse is send into the cable. The cable has certain properties, its characteristic impedance is an important one. If that ch. imp. changes at a certain point in the cable, the pulse will partly reflect back. It is similar to waves in a water reflecting against an object floating in the water. For more info, Google: "transmission lines" Basically any cable is a transmission line so the theory always applies. \$\endgroup\$ – Bimpelrekkie May 31 '17 at 15:15
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    \$\begingroup\$ With a long enough test cable, you may be able to visually see effects with an everyday oscilloscope. If you are trying to do a "science fair" type project, using the USB/Ethernet/GPIB/Serial interface to read the captured data out of one for analysis might work. \$\endgroup\$ – Chris Stratton May 31 '17 at 15:25
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    \$\begingroup\$ allaboutcircuits.com/projects/… \$\endgroup\$ – Bruce Abbott May 31 '17 at 20:39

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