I am trying to create a setup for some Physics experiments - so my background is Physics, not Electrical Engineer that can do circuit design. But I can put a circuit together. I need to amplify the current of a signal from an arbitrary waveform generator. I also need to make sure that any amplification circuit I attach to the waveform generator cannot damage the waveform generator.

The current hardware I have is a Tektronix AWG610 Arbitrary waveform generator and a Tekpower TP3005T Variable Linear DC Power Supply, A constant current or constant voltage power supply it can go up to 5amps. The waveform generator is capable of 400 fs Edge Timing, which I need to preserve as much as possible on the amplified side.

So I am looking for a circuit diagram that would be able to use the signal from the AWG610 and use it to basically modulate the current from the power supply or alternatively basically amplify the current of the AWG610 generated wave form using the separate constant current power source. But If possible I would like the amplifying circuit to be a little more flexible and be able to handle higher amps for when the power supply is upgraded, so maybe 100amp in future. I also need the amplifier to be able to support from low frequency up to at least 1Ghz.

The waveform maybe arbitrary, might be just pulses or a really noisy erratic waveform.

My budget is around $300.

Thanks, any help is much appreciated.

  • \$\begingroup\$ You are aware the inductance of your conductors alone will hamper your plan. There's a reason why GHz circuits are either low-power or high-voltage. \$\endgroup\$
    – Janka
    Jun 5, 2017 at 23:09
  • \$\begingroup\$ Those are some tight specs for 300$... my advice would be to find what your current day fastest edge time is, how much current you really need, and what is your output type, square wave? If so then it is easier because you can use a simple half or full bridge that only amplifies square wave pulses. \$\endgroup\$
    – MadHatter
    Jun 5, 2017 at 23:24
  • 2
    \$\begingroup\$ I'd be willing to pay $1000 for a device that would: (1) accept an arbitrary voltage waveform; (2) preserve \$400\:\textrm{fs}\$ edges; (3) work up to \$1\:\textrm{GHz}\$; and (4) handle "maybe" up to \$100\:\textrm{A}\$ compliance. :) Now that's an opamp! \$\endgroup\$
    – jonk
    Jun 6, 2017 at 0:07
  • 1
    \$\begingroup\$ 5A in 400fs? Assuming 50R load, that's 625 MV/us (that's Megavolts per microsecond)! Even with a 1R load, it's still 12.5 MV/us...if I mathed right. OP, I'm no expert in this sort of equipment, but from the slew rates alone, this kind of stuff requires mucho dinero and very specialized designs. \$\endgroup\$
    – uint128_t
    Jun 6, 2017 at 0:58
  • 2
    \$\begingroup\$ You seem a bit light on firm specifications, but would like the moon on a stick with sprinkles, so let's offer some practical advice. Go to the big three, Analog, TI and Linear, perhaps add Maxim, and look for their fast op-amps. Choose one, build a follower, and see how it does in your application. Hint, you can usually buy ready-built demo boards for the faster ones, for a quick try. For example, I used THS3901, 4 in parallel, as the output grunt for a project a decade or so ago. Once you've got something fast enough, paralleling can give you the current. \$\endgroup\$
    – Neil_UK
    Jun 6, 2017 at 4:59

1 Answer 1


Let's try to put this in perspective.

For the moment, let's ignore the amplifier itself, and assume you already have it. Let's just look at what it takes to get your 5 V, 100 Amp, 1 GHz signal from the output of your amplifier to a load. For the sake of argument, let's assume this in a lab, where you can arrange things conveniently, so your load is, say, 4 inches away from the output terminals of your amplifier.

To carry a 100 amp load, you normally want at least 4 AWG copper wire (and, depending on distance, 3 AWG may be preferred)1.

As noted above, we're assuming you need to transmit your signal for 4 inches. A quick check shows that 4 inches of 4 AWG copper (at 1 GHz) will have about 72 nH of inductance.

If you plan to drive 100 amps with only 5 volts, the input impedance of you load can be a maximum of R = 5/100 = 0.05 ohms. So, your effective circuit looks like this:


simulate this circuit – Schematic created using CircuitLab

Now, let's think about that circuit for a second. To (even an amateur) EE, that looks a lot like a low-pass filter. A quick run through a calculator shows that viewing it as a filter, those values give a cut-off frequency of about 2.2 MHz. By 1 GHz, it has something like 50-55 dB of attenuation. So, your 5 volts at 1 GHz coming out of the amplifier is down to about 10 millivolts at 1 GHz by the time it gets to the load.

Bottom line: with the kind of specs you're talking about (100 amps at 1 GHz), just getting the electricity from the amp to the load successfully becomes quite a non-trivial undertaking (and, of course, at a greater distance, the inductance increases, and with it the impedance).

1. Note: those are based on 50-60 Hz power transmission though. Due to skin effect, at 1 GHz you'd probably need something even larger (or something of that effective size, but made of of many fine strands).


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.