I have a CNC controller that outputs 0-10v PWM signal voltage for the purpose of controlling cutting spindle RPM (or in this case, laser power output). This is not the actual driving voltage, this is a signal voltage (I hope that makes sense). My laser engraver requires 0-5v PWM signal, so I essentially need to cut the controller's output voltage by 50%.

I am not an electronics expert by any means, but I can successfully put a circuit together. I have op amps, resistors, capacitors, and diodes at my disposal, so hopefully it can be done with what I have on-hand.

Thank you very much for any help.

  • \$\begingroup\$ No, I don't have that information. I could probably get it from the manufacturer though. \$\endgroup\$ – Bill Blades Jul 2 '17 at 18:24

Since you apparently just want to divide a signal voltage in two and have no current requirement:


simulate this circuit – Schematic created using CircuitLab

This is called a voltage divider.

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    \$\begingroup\$ Answer could be improved if you refer to issues in this solution taken into account outgoing impedance and the advantages of add a op amp or more improved voltage dividers. \$\endgroup\$ – pasaba por aqui Jul 2 '17 at 14:25
  • \$\begingroup\$ Indeed. I was half expecting the question to be closed as there are numerous other questions, even recently, that are essentially the same. \$\endgroup\$ – replete Jul 2 '17 at 14:28
  • \$\begingroup\$ I did actually search first, and found voltage dividers, but they seemed to be @ dedicated input voltage. I wasn't sure if this would be the best method, being a variable source voltage. \$\endgroup\$ – Bill Blades Jul 2 '17 at 18:29
  • \$\begingroup\$ add a voltage follower op amp to the divider circuit so that the output voltage does not change as a result of the impedance of the circuit connected to the divider circuit. \$\endgroup\$ – Paul Blakeney Feb 11 '18 at 23:57

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