The Q-factor is often defined as Q=resonnance frequency/bandewith. Suppose we take this definition and take two LC circuit which both have Q=1 but the first resonnant circuit has a resonnance frequency of 1 and the second one has a resonnance frequency of 10. This means that the first circuit has a bandewith of 1 and the second one has a bandwith of 10. But if this is the case, I would say intuitively that the second circuit is less selective because it has a bigger bandwith. But the Q are the same so one says the selectivity is the same. It seems weird to me that in the formula of the Q we don't just have Q=1/bandwith. Why is that?


But does it makes sense to say that the Q factor characterises the pic in the frequency domain even though in the figure just down here the shape are exactly the same but the Q factor are different?

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    \$\begingroup\$ Q is perhaps best appreciated as a figure of merit, as an analogy its easy to make a 1 ohm resistor to the nearest ohm, it is extremely to difficult to fabricate a 1MegOhm resistor to the nearest ohm \$\endgroup\$
    – sstobbe
    Jul 2, 2017 at 17:03
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    \$\begingroup\$ You are confusing the resonant frequency with bandwidth. Bandwidth of the circuit can be the same at resonant frequencies of 1MHz and 100MHz (though harder in practice with real components). \$\endgroup\$
    – filo
    Jul 2, 2017 at 17:26


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