I'm trying to understand how the below circuit allows interfacing LVDS levels with LVPECL levels.
Voh = 1.4V, Vol = 1V, Vcm = 1.2V
VBB = 2V
After the transmission line, the AC coupling caps remove the DC common mode of the driver so that Voh = 0.2V and Vol = -0.2V, correct? I assume VBB sets the common mode of the receiver at 2V, so does that mean the inputs to the receiver are:
Vih = 2 + 0.2V and Vil = 2 - 0.2V?
And also is the bypass capacitor on VBB absolutely necessary?