I am confused about something regarding the quartz crystals. More specifically I cannot understand the difference between the effective or equivalent series resistance (ESR or \$R_e\$), and the motional resistance (\$R_1\$).
Below is the typical equivalent circuit of a crystal (source is the AN-1260 App-Note from Analog).
There is also a formula giving the the equivalent resistance at a given load capacitance \$C_L\$: $$ESR = R_1 \cdot \left( 1+\frac{C_0}{C_L} \right)^2 $$
The way I understand it is that the ESR includes \$R_1\$ and also the resistive parts of \$L_1\$ and \$C_1\$. Is that true?
My confusion is actually related to how should I calculate the power dissipated in the crystal (drive level). I mean generally, we can say the power is equal to $$P = I^2 \cdot R$$ but which "R" should we put there? Is it the resistive losses, thus the motional resistance \$R_1\$ or the equivalent series resistance ESR?
I would personally use \$R_1\$ but there seems to be a confusion in the literature. So the application note I have linked before uses obviously \$R_1\$ and the same do other sources like the AN826 App-Note from Microchip or the AN3208 App-Note from NXP. But other sources use the ESR, like the SWRA495 application report from TI or the AN2867 App-Note from ST!
So, what is the correct resistance to use?!