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I wanted to implement the function:

$$Y = \neg (A \land (B \lor C))$$

This is what I came up with, it looks correct to me but I would like a second opinion on that.

schematic

simulate this circuit – Schematic created using CircuitLab

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    \$\begingroup\$ 'it looks correct" - I've had many circcuits that looked correct but turned out to be wrong - that is what simulators are for \$\endgroup\$ – Joren Vaes Aug 23 '17 at 9:15
  • \$\begingroup\$ sorry I dont know how to simulate this or any kind of circuit \$\endgroup\$ – zython Aug 23 '17 at 9:17
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    \$\begingroup\$ Yet you entered your circuit into a simulator. I'm not an expert on digital simulation, but you could easily just write out a truth table for this logic function, and then do a DC operation point analysis to find all the output voltages of the different nodes (And thus your output) as a function of the input. A lot of simulators will even allow parametric sweep with which you could do the entire simulation of this in one run. \$\endgroup\$ – Joren Vaes Aug 23 '17 at 9:19
  • \$\begingroup\$ sorry I thought the tool was just for designing schematics. can you maybe link me where I can get started quickly to simulate the circuit ? \$\endgroup\$ – zython Aug 23 '17 at 9:20
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    \$\begingroup\$ How about the "simulate this circuit" button next to the image? \$\endgroup\$ – Brian Drummond Aug 23 '17 at 9:22
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From your drawing, I derive this:

schematic

simulate this circuit – Schematic created using CircuitLab

Your 10T implementation is correct.

There are alternative 6T implementations as an OAI complex gate:

schematic

simulate this circuit

The OAI could be as drawn or the nFETs can be rearranged.

(Note that the bulk nodes of the stacked FETs are drawn inappropriately. I didn't intend to imply these are discrete ICs with the source and bulk nodes shorted... this is just what I pulled from the library.)

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