In the figure shown, Vi is a 100 hz triangular wave having a peak to peak amplitude of 2 volts and an average value of 0 volts. Given that the diode is ideal, the average value of the output voltage Vo is ________.
I took an assertion that at the moment when the input voltage is 1v(it's maximum), the diode is reverse biased. Then using voltage divider, the voltage across the resistor turned out to be Vi/2 i.e 0.5 volts. Voila ! The assertion is indeed correct.
That means the output voltage will just be a copy of the input voltage dimnished by a factor of 1/2.
I.e a 100 hz triangular wave having a peak to peak amplitude of 1 volts.
Therefore, the average value of the output voltage is zero.
Is this answer correct ? And if yes, can we also take the opposite assertion assuming the diode to be forward biased and then prove it wrong. If yes, how ?