(It's really a continuation of a previous question but it is old so I decided to ask a new one with more detail)
I have a colpitts oscillator designed for 27 MHz going into a short monopole antenna of 1/20 of the wavelength, or 55 cm. The radiation resistance is 2 Ohms, with capacitance of 5 pF (calculated with this calculator). This means that to bring it to the resonance I am to use 6.9 uH inductor, according to the same calculator. My colpitts oscillator has output impedance of 300 ohms, which I matched to 50 ohm load. If I understand correctly now I have to make my 2 ohm real resistance load look like it is 50 ohm load. So here's what I came up with:
simulate this circuit – Schematic created using CircuitLab
I am not sure if this is really done this way. Is the impedance of the antenna (after I include tuning inductor of 6.9uH) really 2 ohm real resistance, or is it calculated in some other way? The other question is if matching both the source and the load to 50 ohms is done this way, or the calculation for when both of them should be matched is different (I am not sure if the L and C elements from different L networks would influence each other and the outcome?