4
\$\begingroup\$

I have been designing a 100 watt, high frequency (20 - 40 kHz), bridged amplifier using MOSFETs. Although I have some systems and electronics background, the behavior of the MOSFETs is a bit beyond my understanding.

I have managed to smooth out the noise and remove most of the crossover distortion by adding a zener diode bias network. The left-hand op amp increases the signal (sine wave) to the full voltage range (within the swing of the op amp). The right-hand op amp takes the output of the left-hand and inverts it with unity gain. I know that this can amplify the distortion of the first op amp, but that isn't really a concern for this project. The output is shown below for the left (vl) and right (vr) sides:

Left bridge waveform vs. Right bridge waveform

The problem is that the unity gain amplifier (waveform vr) seems to not actually have a gain of 1, but instead 1.1 or 1.2 when I perform a simulation in LTSpice. This results in an unbalanced output waveform that is not desirable. Notice the higher peaks on the red waveform -- these should be the same amplitude as the blue peaks. I can reduce this effect by reducing R8, R9, R15, and R16, but then the power over these resistors becomes too great. Without the MOSFET bridge on the output, the op amp is indeed unity.

  • Is there an effect that I am missing that causes the op amp to swing higher when attached to the push-pull?
  • What would be the course of action to correct this circuit? I am fine with minor distortion, but I would prefer a balanced output.

Also, is it wise to use zener diodes to provide the voltage bias to the MOSFETs? It seems to perform fine in simulation, but I'm not sure if it might not in a production circuit (with 100 W output). Is there a better way to provide this bias?

MOSFET H-Bridge Schematic

\$\endgroup\$

2 Answers 2

5
\$\begingroup\$

You are taking the U3 drive signal from the wrong place.

enter image description here

Figure 1. Marked up schematic.

Instead of taking the signal from (2) you should be taking it from (3).

The problem is that (2) is a distorted signal as it has to overcome all the distortion caused by D2 / D3 and M1 / M2. You are tapping off part way inside the feedback loop of U2.

Your other option is to take it from (1) but configure U3 as non-inverting amplifier with stage gain the same as left side.

\$\endgroup\$
1
  • \$\begingroup\$ This was indeed the problem. Both answers are great, but I accepted this one for the visual schematic that may help others. Thank you! I value the simplicity of two inverting amplifiers more in this case. \$\endgroup\$
    – Two Nybble
    Aug 29, 2017 at 18:16
4
\$\begingroup\$

You are feeding the output of the op-amp U2 to U3, not the output of the amplifier stage itself .. ie. VL..

U2's output will be greater than VL.

You should really drive the right side from the source signal though, either an added invert stage or use a non-inverting amplifier on the right.. Reason being, you can affect the right side by messing with the left output.

\$\endgroup\$
1
  • 1
    \$\begingroup\$ This was indeed the problem, seems so obvious now! I don't mind the distortion from not driving from the signal for this particular project -- I value the simplicity of two inverters more here. Thank you! \$\endgroup\$
    – Two Nybble
    Aug 29, 2017 at 18:15

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.