Plz tell me the use of resistor R1 and capacitance C(s) and C(e) in the given circuit and also their necessity.
R1 and R2 form a resistor ladder with a voltage that with no signal from the input will be somewhere between Vcc and 0. This is to bias the transistor so that it is always conducting at least some. The capacitor Cs is a blocking capacitor to keep any DC portion of the input signal out, so we only see the changing part at the base of the transistor. CE is there to shunt any HF part of what the emitter sees to ground. Given no actual values for the components we can only describe what they are doing, not how much of it.
To elaborate a bit on the precious answer, an NPN transistor needs about 0.6V on the base in order for it to turn on. R1 is there to pull the base voltage up so that the transistor is on.
Without it, the transistor would be completely off the negative cycle of the AC input, and also for any part of the cycle less than 0.6V.
Cs isolates the bias voltage produced by R1 and R2 from any DC component present in the input signal. It only lets through the AC.
As zeta-band has said, Ce will tend to dump any high frequency components that get through the amplifier, by effectively shorting them to ground. Presumably the designer of this circuit didn't want them. High frequencies could include noise signals that are above any expected input frequency.