# Why the resistors needs higher Ampers if the Total current is 4 Ampers? I have a question about the circuit as shown up. My question is if the total current is 4 Amperes, why do the resistors need a higher current?

Am I missing something? If that so, what it is?

• Your calculations for I1 & I2 are not correct. R1 & R2 do not have 64V across them because there is a 48V drop across R3 (4A x 12 ohms = 48V). – brhans Sep 8 '17 at 2:04
• To expand on brhans comment. The voltage across R1 and R2 is only 16 volts (64 times (4 /16)). Then the current through R1 is 16/12, or 1 1/3 amps, and the current through R2 is 16/6, or 2 2/3 amps. Total current is 1 1/3 plus, 2 2/3, or 4 amps. – WhatRoughBeast Sep 8 '17 at 3:11
• What do you mean, the resistors need a higher current? They don't. – Brian Drummond Sep 8 '17 at 9:30

Now to finish off, you need to use the correct voltage drop for each series resistor. Using Ohm's Law the other way round, the voltage drop is given by $V=IR$
For: R3, $12\Omega$ * 4A = 48v
For: R1 || R2, $4\Omega$ * 4A = 16v