We know that we receive the programs/shows of TV Channels from the producers of programs through
- CATV Service providers (almost obsolete, just wanted to get clarified on its working process)
- DTH Service.
Consider that a TV Channel produces programs and wants its programs to be telecasted to a wide audience. It will request a CATV Service provider to telecast its programs. After an agreement, the producer/channel will send his programs to the service provider. The service provider will then allocate a unique number to that channel. Transmission of the programs produced by the channel will be enabled through a Coaxial Cable.
Now, a single RG-6 coax cable can carry multiple channel programs with the concept of Frequency Division Multiplexing whereby, each channel will be allocated a bandwidth of 6-7 MHz. Typically 166-200 channels will be transmitted through the same single RG-6 cable.
My queries are
Will the Service provider transmit an AC of radio frequency for all the channel programs into the cable, which gets converted to EM waves and reaches the 3-way splitter?
Is it just an assumption that the two currents in the coax conductors need to be equal and opposite in order to not radiate outward?
Provided that each channel can occupy only 6-7 MHz band, is it obvious that each program produced by the channel will be transmitted at frequencies within this band? And, if 0-6 MHz is allocated for channel A, 7-12 MHz will be allocated for channel B? To avoid overlapping of frequencies?