I am having a basic doubt regarding the working of preset and clear inputs.
Consider these two figures:-
Here in figure 1, if clear is 0, then Q will be 0 from 1.
But if its active low signal as shown in figure 2 then if clear is 0, then it will be inverted and clear input will be 1. So how will the output Q be 0 if clear input =1 ? I think it should not be inverted so that we can directly pass the clear input which is 0 and get output Q as 0.
I am not able to understand the meaning of active low signal and it's use here. What is the actual meaning of active low signal ? Is it just like attaching a NOT gate for input or does it mean that circuit will be active for low inputs but the inputs remain the same and not get inverted?