# Instantaneous voltage drop acrossed resistors in series

When two resistors with equal resistances are wired in series the voltage across each resistor is equal to half the voltage of the power supply. Is this also the case the instant the power supply is turned on? At the instaneous moment when the electric current has just reached the first resistor in series is the voltage across that resistor equal to half the voltage of the battery or all the voltage of the battery? In the case of the former being true, how is the current "aware" of the second resistor in the circuit before encountering it? In the case of the later, how does the circuit eventually reach equilibrium?

• Effectively, yes. If a charge moves in at one end then one is pushed out at the other end. The speed of propagation of the EM (electromagnetic) wave is close to the speed of light. For most low frequency applications we just consider that the current is instantaneously the same through all points on that branch of the circuit. Sep 17, 2017 at 17:35
• It sounds as though you want to know how it is that charges are aware of "how to move" in a circuit. So, for example, how is it that a current of charges "knows" to split in a certain proportion when they reach a Y in a wire, dividing up so that some portion moves down one path and a different portion moves down another path, as it is impossible for them to "know" what's ahead. Is that it?
– jonk
Sep 17, 2017 at 18:00
• @Transistor unless of course the wires between the resistors are very very very long. Then you may get into considerable measurable transmission line effects.. Sep 18, 2017 at 18:32
• @jonk Yes, that is essentially my question. It seems as though the current is able to foresee the path it is going to take. Sep 18, 2017 at 18:42
• @Jgbcode I think the best way to figure this out would be to get and read Chabay & Sherwood's "Matter & Interactions", 3rd edition (or later?), and pay a lot of attention to Chapter 19 there. Also, you will learn from it the difference in meaning between "equilibrium" and "steady" states, as they use these terms advisedly there. Are you willing to accept a simplified answer? (The book is better than I would be, so if you'd prefer to get the book that is fine with me.) +1 as now this is a good question, I think.
– jonk
Sep 18, 2017 at 21:10