# opamp output voltage

I was trying to solve the below question. As per my understanding at t=0+ the difference voltage between (Vnoninvering -Vinverting)=-2.5v so output will change to -5. After then as Vin increases it will behave like normal noninverting amplifier with gain 2. The output will be distorted to give 5v.

Edit: The question is to draw output waveform Vo over time where time varies from time=0 to time= infinity.

• I am still not clear what you want to know? My guess is the transient nature of opamp (at t=0+)!! Sep 21, 2017 at 6:09
• As per my understanding at t=0+ the difference voltage between (Vnoninvering -Vinverting)=-2.5v Explain why you make that (wrong) assumption. An opamp in with negative feedback will always try to make the input voltage difference zero. Only when it cannot do that you should assume otherwise. Sep 21, 2017 at 6:36
• @Bimpelrekkie: He's not assuming it; it's stated in the image. It must be a start-up transient. Sep 21, 2017 at 7:13
• @Transistor OK, you conclude that from intitial Vo = +5V so - input = 2.5 V but +in put is 0 V. That makes it an inconsistent question as no information is given about the transient behavior. Also, the situation Vo = 5V while Vin = 0 V is not a proper solution for this circuit. I think Vo = 5V initially is a typo and should say: Vo = 0 V initially. Sep 21, 2017 at 7:31

• At t = 0 $V_+ = 0$ so $V_- = 0$. This means that $V_{OUT} = 0$ too.