# What would happen to the DC bias voltage of the emitter if this capacitor is omitted?

I'm not quite sure what the question means. I need to explain what would happen if I removed the $1.0 \mu F$ blocking capacitor from this circuit. Howver, I'm not sure what the "DC bias voltage of the emitter" is. Is it simply the voltage as measured from base to emitter? This is for a 2N3904 transistor and an emitter-follower setup.