Judging from the IRL8743PBF datasheet you linked, you might be in for a bumpy ride if you drive them straight from a logic pin.
You say it "can be switched to fully-conductive by a 3.3 Volt logic signal", but that's not true. To get its rated 3.2mΩ, you have to use a 10V Vgs signal, see "Rdson" in the table on page 2. At 4.5V Vgs, you're guaranteed 4.2mΩ. There is no guarantee specified for 3.3V.
However, judging by fig.3, the current is about 5% at 3V, suggesting a 20-fold increase in Rdson (let's call it 100mΩ). Looking at fig.12, you can see the Rdson is off the charts for Vgs=3V.
You mentioned a load current of 1A. If my estimated ~100mΩ is correct, that's 100mW dissipated at 0.1V drop, which sounds perfectly reasonable, but all this is based on estimates from typical values. Not facts of worst-case values.
You're probably better off driving them from a higher gate drive voltage (4.5V will do. You can't use the 24V, too high), with a NPN transistor driven by the Raspi to shunt the gate to ground. See the circuit from this EE.SE answer from Majenko for an example:
Another concern with the choice is the maximum Vds voltage which, at 30V, is very close to your 24V. Any significant overvoltage spike (e.g. caused by inductive kickback) could kill the transistor. Be sure to protect against that (e.g. with clamping diodes).
Another warning: the "slow boat" option has a relatively high chance of giving you fake parts that don't quite deliver the promised specs. Better buy from a trusted source if you don't want that risk.