I bought the attached pocket heater. The elevated element seems to be heater spirals so the red cables seem to lead to short circuit - capable circuitry.
Background: So I built this tight case for my ipod 5G nano and connected it to my suit to not be forced to buy a GoPro or something like that but still have a nice video documentation of my sports activities. Tight means, once the ipod is in place it has almost no space to move in the flat plane. But there is space parallel to it, I found the heater to have optimal dimensions for this. So the video recording using the ipod lasts about 1:39 hours continuously. Then the battery charge is gone. But also in the operating system if being connected to a power source after 1:39 hours recording stops. So my goal is to have a portable power source connected to the ipod via usb-cable. Then each 1:39 hours the alarm of my mobile phone goes off reminding me to get the ipod out and press record again, which is doable. But I also wrote to apple for them to include such a feature in the next firmware update. So this is what the following is for. The following shows the plug. I need to bend it at the dashed line for it to fit inside the case. I have not found another (flat) plug yet, and the current one contains a pcb which won't let me bend it I presume. So I need to find another way.
By attaching a USB-cable the device is being charged. The following image seems to show the battery:
My goal is to use it as a power source for 5V USB. Either by being able to reverse the current flow, ie by pressing the button on the lower left in the following image. It should supply 5V, 500mA at the USB-connection...
... or by drilling holes into the upper plastic being seen here...
... to apply an USB-Plug or Socket externally.
How would you do it given the current pictures, where would you connect what and why? What would you measure where?
My ideas are to replace the red wires, connect one of the wires to the switch for it to only connect to the USB-cable when not charging. Problem is: There is not 5V but something around 3.5Volts in between. Also in how far do I need to take the short-circuit-proof circuitry into account.