I'm reading "Op Amps for everyone" (http://web.mit.edu/6.101/www/reference/op_amps_everyone.pdf) and I'm currently studying the chapter about the compensation of op.amps. but I'm missing a passage. At page 111 after explaining why a loading capacitance can add another pole which can shift the phase and decrease stability, it is written that if Zo << Zf the closed loop transfer function is easy to calculate because the loading capacitance IS enclosed in the feedbackloop.
I mean, if the output impedance could be considered a "shortcut" then the output capacitance is excluded from the feedback loop. In fact the next page it is written that the closed loop transfer function is the same as the non inverting op amp one. What I'm missing? Thank you.