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Usually audio inputs use protection diodes that shunt into the power supply rails of the device they're protecting. But is this really necessary? Why are TVS diodes not used here? Yes, some are high capacitance. But they have low capacitance parts that are ~3pF or less for DSL modems and such. If a TVS diode can shunt from input pins to the chassis at the entry point of the enclosure, would that not be better?

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    \$\begingroup\$ TVS's tend to have higher leakage (even with stearing diode topologies). Considering audiophiles complain if they don't have 99.99999% copper, image if they also had to argue about leakage current \$\endgroup\$ – JonRB Oct 21 '17 at 22:43
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    \$\begingroup\$ Audio cable plugs often discharge ground contacts first, so Input signal protection is redundant. \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Oct 21 '17 at 23:12
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    \$\begingroup\$ @TonyStewart.EEsince'75 You mean a 1/4" plug because of the way it makes contact to ground first? What about XLR? \$\endgroup\$ – squarewav Oct 22 '17 at 3:01
  • \$\begingroup\$ That’s what I said, XLR is low impedance thus low voltage \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Oct 27 '17 at 22:31
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TVS is for power section of electronics. Small signals that are forwarded to amplifiers would suffer from leakage currents. A high impedance of amplifier input has to be protected by low leakage diodes, less than pA. A JFET transistors are used as diodes, range of 100fA (femto amperes).

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    \$\begingroup\$ Signal diode leakage is uA. Why exactly does it need to be "less than pA"? Is there some kind of non-linearity that is a problem? \$\endgroup\$ – squarewav Oct 22 '17 at 2:58
  • \$\begingroup\$ It could be a temperature concern too. TVS and many standard diodes leak like sieves at higher temps (e.g. going to hundreds of uA or mA if the diode was large enough). \$\endgroup\$ – Zekhariah Aug 7 '18 at 14:43

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