From http://www.electronics-tutorials.ws/amplifier/amp_2.html, i understand that the voltage gain of a common emitter BJT is given by below equation; where RL is the load resistance, RE is the resistance between emitter and ground and Re is an inherent BJT emitter resistance.
This voltage gain is applicable for both AC/DC input voltage. How about the biased DC voltage? Does it get amplified as well?
Basically i would like to know whether a BJT (common-emitter example) also amplifies the biased voltage (applied at the base). In the absence of any input voltage, can i say that the output voltage (at the emitter) is equal to biased voltage (0.7V for example) multiplied by the voltage gain [-RL/(RE + Re)]?