While I am aware of the risk associated with charging Li-ion below 0 °C and that the charge acceptance for a NiMH battery decreases with rising temperature, I am finding conflicting information when it comes to charging NiMH batteries below 0 °C.

Battery University in Table 1 claims that 0°C to 45°C is the charging temp range.

Energizer in Figure 13 claims that the battery will charge at -10°C

Is it possible to charge any NiMH battery below freezing? Is it dependent on the actual battery itself? If it is not able to be charged, why not?



  • 3
    \$\begingroup\$ Charges well at 0 to to 45. Below freezing it's less efficient, but the charging leads to temperature increase internally. What's the actual use case here? \$\endgroup\$ – Passerby Nov 9 '17 at 18:59

It's not a hard line. The battery doesn't just quit at -0.00001 degrees. It depends on the battery internal temperature and the status of the liquid electrolyte inside the battery. If it is frozen, no chemical reaction can take place. As Energized states, it will charge at 14 degrees F, 10 C, but it has half the normal capacity it would.

See http://www.robotroom.com/Weather-Station-Data-2.html for a empirical look at temperature vs charging results.

  • \$\begingroup\$ "As Energized states, it will charge at 14 degrees F, [-]10 C, but it has half the normal capacity it would." - This is for discharging, not charging. Can some NiMH be made to charge at these sub-zero temperatures? - Without the use of heating elements \$\endgroup\$ – SNM Nov 9 '17 at 20:02
  • \$\begingroup\$ @snm capacity while discharging at -10 c is lowered. Their charge chart on figure 13 shows it charging at -10 c though. It can charge under freezing, the specifics being how frozen the cell is and how the charging itself can lead to heating, etc. \$\endgroup\$ – Passerby Nov 9 '17 at 22:57

Take care! It´s no recommended charge the battery at this temperture. Take note about the specifications of the battery, and the battery charger and the experts in this field (Amperis) Regards


Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Not the answer you're looking for? Browse other questions tagged or ask your own question.