From what I’ve learn at SS we consider the capacitor as an open circuit. Therefore the bottom line connects the circuit on the left (current source ) with the circuit on the right (voltage source ) .
I’m specifically interested in what happens at the node bellow 5kΩ. Since it connects with the voltage source part of the current coming from the resistance has to go towards the right circuit. But that current never goes back to the current source. I can’t use any of my techniques (node or loop analysis ). It might be possible but this circuit seems a bit odd for me to follow my usual steps.
Well, the voltage drop across the 5kΩ is 50 Volts. If the current goes to the right there is another voltage drop of 4V so the total Voltage difference across the capacitor is 54?
Does the current source provide power to the right current ? What is the potential before entering the current source ?