In the circuit below, all of the resistors are 15 Ohms. I am trying to find the equivalent resistance between A and B.
Can we argue that since RAD/RDC = RAO/ROC that AODC is a wheatstone bridge and thus say no current will flow through DO and remove DO from the circuit? Using the same argument, can we remove BO too?
Can we then just simplify the circuit like below and then find the equivalent resistance using the series and parallel rules?
O
andD
. It is wrong because of the current that flows through the resistor between nodesO
andB
. \$\endgroup\$