enter image description here

Why would you put multiple resistors in line instead of one resistor that is the same value? In this case, I have a PCB with three 1k ohm resistors. What could be the reason for this instead of just one 3k ohm resistor? Thanks in advance!

  • 1
    \$\begingroup\$ Usually to share voltage drop or power dissipation... In this case what is V and I? My guess <10mA and 24V. Subtract diode drop and Pd = V²/3k = 161 mW shared by 3 small chips. \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Dec 2 '17 at 1:07
  • 1
    \$\begingroup\$ If it is 24V then this is probably for power dissipation - 0603 resistors are 1/10W. \$\endgroup\$ – τεκ Dec 2 '17 at 1:13
  • 3
    \$\begingroup\$ Not this particular case, but sometimes we do it for redundancy - where a failure open puts the device in a safe condition but a failure short could result in an undesirable outcome. \$\endgroup\$ – Spehro Pefhany Dec 2 '17 at 2:32
  • 10
    \$\begingroup\$ Are you sure that they are physically connected "in line"? I often line resistors up on my PCB but they aren't series'd together. The traces come in from the sides. \$\endgroup\$ – Ron Beyer Dec 2 '17 at 3:44
  • 1
    \$\begingroup\$ Nice photo. I appreciate the clean background. \$\endgroup\$ – A. I. Breveleri Dec 2 '17 at 16:02

Three reasons I can think of:

  1. to allow for a higher power dissipation than one resistor can handle.

  2. to tolerate a higher voltage than one resistor can safely handle.

(Higher power or higher voltage resistors would be larger, which may not be convenient for the auto-place machine)

  1. to minimize the number of different resistor values required on the board (if I use lots of 1K resistors elsewhere, it may be cheaper to use three here, than to buy a few 3K resistors to use in one place)("cheaper" may include loading and programming the auto-place machine as well as the actual cost of the resistors).
  • 8
    \$\begingroup\$ 4. to get the average resistance (since every resistor has a tolerance) closer to the actual value \$\endgroup\$ – Ferrybig Dec 2 '17 at 11:18
  • 12
    \$\begingroup\$ @Ferrybig That's not a guarantee, even statistically, since resistor values aren't always nicely distributed. If you actually need the tighter tolerance, buy it. \$\endgroup\$ – Abe Karplus Dec 2 '17 at 12:12
  • 9
    \$\begingroup\$ @Ferrybig It doesn't work that way, rather the opposite. \$\endgroup\$ – itsLex Dec 2 '17 at 16:10
  • 6
    \$\begingroup\$ @Andrei Because you will still produce a big lot of outliers. Averaging three Gaussian variables gives a little guarantee. Moreover, if all three come from the same lot, they can all be equally biased by some systematic margin, and you are lost anyway. \$\endgroup\$ – yo' Dec 2 '17 at 16:59
  • 7
    \$\begingroup\$ @LamarLatrell No. It's not a lottery with fair and random results. It's a spec. If I have a batch of resistors all reading exactly 1030 ohms each, I sell them as "1k, 3%". You know that you are averaging but you have no idea what are you averaging, which makes the process useless. If you need more precision, you buy better tolerance, if you don't need the precision, why bother? \$\endgroup\$ – Agent_L Dec 3 '17 at 10:07

It may be a reason of power dissipation. Each resistor package of that size can support only a certain amount of power on the resistor so putting multiple in series spreads the power across multiple packages.

Another reason may be voltage rating. An SMT device like that will have a MAX voltage rating that it can handle without insulation break down. Multiple resistors in series will split the voltage drop across the various devices.

A last reason that this is sometimes done is that the circuit board design is done to it is easy to swap out certain resistors to be able to select a combination of different valued resistors that total up to certain calibrated requirement that may not be available in a standard valued single resistor.

  • \$\begingroup\$ I have seen cases where resistors are put along each lead, say, a the power line and the return one. Think about wanting to have a voltage source with a series resistance of 300kOhms. I've seen applications where one 150k goes in series with each lead. Why would be the use of this? Thanks \$\endgroup\$ – Big6 Dec 2 '17 at 1:17
  • 1
    \$\begingroup\$ @sixcab Same reasons. \$\endgroup\$ – user253751 Dec 2 '17 at 7:35
  • \$\begingroup\$ @immibis I guess my question is, instead of placing resistors along each lead, why don't you put them in just a single lead? Say you want to create 10k and for that you use two 5k's. What would be the difference between placing a 5k in series with each lead of the source vs placing the 5k's in series with a single lead? \$\endgroup\$ – Big6 Dec 3 '17 at 17:26

In this case, reduction of production cost. Using a common value three times (1k) instead of a less common value once (3k) reduces the total number of different parts required by your design. In the pick and place process used in manufacturing, you are looking to minimize the number of different parts used, within reason. Loading new reels into the feeders can be a significantly greater cost than using a couple more of the same part.

Other reasons to make a chain like this can include increasing the effective voltage rating of the part, such as in the high voltage frontend of a meter or probe, but that doesn't apply here.

  • \$\begingroup\$ My answer jumps to conclusions. It doesn't look at all like a voltage tolerance case, but may well be for power or swap-out reasons as mentioned in other answers. Power in particular looks likely based on what is nearby. \$\endgroup\$ – replete Dec 2 '17 at 1:11
  • 4
    \$\begingroup\$ Yeah. Those big-ass screw heads surrounded by a field of plated thru holes suggests the presence of a heat sink on the other side. \$\endgroup\$ – WhatRoughBeast Dec 2 '17 at 14:38

I wonder if the board has three resistors in a row because that's what the circuit needs: they aren't just substituting for a single resistor with three times the resistance.

Look to the left between each of the triple resistors, e.g. just above the "3" in the R23 label. Aren't those vias? It looks like there's a via next to each of the junctions in all of the triple-resistor groups. (Someone please let me know if I'm misinterpreting the photo.)

So my guess is the three resistors in each group could be wired in series, thus the placement, but there's also a tap at each of those junctions running to some other part of the circuit.

Or maybe the vias are there for some other reason of convenient layout - but it does seem like an interesting coincidence.

(Also, thanks everyone for the other answers! Always fun to learn some things about PCB manufacturing.)


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.