4
\$\begingroup\$

If I have a signal generator with 600 ohm output resistance and a 8 ohm speaker. The number of turns in primary coil is 50, so the turn ratio should be $$\frac{600}{8}=(\frac{N_2}{50})^2 \\N_2=433\\N_1:N_2=50:433$$ Furthermore, will there be any difference on maximizing the power output with applying different frequency output in the signal generator!? such as 1khz vs 5khz.

\$\endgroup\$
7
\$\begingroup\$

You've got it backwards. You have a 600 Ω signal and want to drive a 8 Ω load. Apparently you are trying to do this with a transformer between the two. Clearly the primary needs to have the higher number of turns.

Your resistance ratio is (600 Ω)/(8 Ω) = 75. The turns ratio needs to be the square root of that, which is 8.66. (50 turns)/8.66 = 5.8 turns. That's what the secondary should be.

| improve this answer | |
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.