Here's a switching circuit. The input Vs is a 24V rectangular pulse at 20kHz frequency with 75% duty cycle. Since the time constant L/R is very much greater than the pulse width, we expect the inductor current to be a triangular wave (i.e. integral of a rectangular wave) at a certain DC offset which is the average current. My problem is, how do you find the average inductor current assuming Vbatt is 13.8V? (Please ignore questions b and c.)
Only guidance, not something to copy as is:
The time constant L/R = 1 second. That's enormous when compared to the pulse interval. The current in the inductor does not change remarkably, probably not even measurably during one pulse period. You can well think your pulse source as a constant voltage DC source. The voltage of it is the average pulse voltage.