# Bridge Full Wave Rectifier

I'm trying to do a problem for class and I'm having trouble on clarification and where to start.  I understand how the turns ratio works, but I don't know how to find it here. I can't find anything in my book or in handouts; I only find them when there are resistors on both sides.

I'm also confused on what VL and Vp are. I think Vp is the peak of the whole wave but I don't know what VL is showing here. Vrpp is also confusing me. I just need some clarification and guidance.

Thanks

• $V_L$ is the load voltage. $V_p$ and $V_s$ are the primary and secondary voltages. $V_{r\ PP}$ is the peak-to-peak voltage on $V_L$. Dec 12 '17 at 18:53
• Ohhh, that makes more sense. So since the voltage across the load is 10, the turns ratio would then be 1:11? Or would I have to take into account the .7 per diode used then use that voltage?
– John
Dec 12 '17 at 18:59
• You need to take diode drops and ripple into account. They made it a bit more difficult by specifying RMS output voltage rather than average. Dec 12 '17 at 20:03