All books and references I read say that RHP zero gives a negative phase shift. I can infer that by plot the phase of the function \$w_{z}-s\$ where \$w_{z}>0\$. With this function, when frequency increases the phase is negative and goes from 0 to -90 degree.

However, with exact the same RHP zero \$s=w_{z}\$ but now I write it in the form \$s-w_{z}\$. If I plot the phase of that function with frequency, the phase is positive and decreases from 180 to 90 degrees as frequency increases.

So is it correct to say RHP zero give a negative phase shift? Maybe there is something obvious I am missing here.

  • \$\begingroup\$ The phase decreases in both of your examples. You have a negative phase shift. For s - wz you multiplied wz - s by negative one (-1). Multiplying by (-1) adds +/- 180 degrees to the phase of a transfer function. \$\endgroup\$ – PICyPICyPICy Dec 14 '17 at 15:46

The correct way to write a transfer function featuring a single zero is \$H_1(s)=1+\frac{s}{\omega_z}\$ and a single pole is \$H_2(s)=\frac{1}{1+\frac{s}{\omega_p}}\$. The plus sign implies that when \$s\$ takes on a negative value, meaning the real zero or pole lies in the left half-plane (LHP), the corresponding \$-s_z\$ and \$-s_p\$ salient values respectively cancels \$H_1\$ and brings \$H_2\$ infinite. The phase leads for the LHP zero and lags for LHP pole.

If you now write \$H_1(s)=1-\frac{s}{\omega_z}\$ and \$H_2(s)=\frac{1}{1-\frac{s}{\omega_p}}\$, when \$s\$ takes on a positive value \$s_z\$ or \$s_p\$, meaning the real zero or pole lies in the right half-plane (RHP), the magnitudes follow the same law as for the LHP roots but the phase now lags for the zero and leads for the pole. A simple plot shows the magnitude and phase for a RHP zero and a pole.

enter image description here

  • \$\begingroup\$ Thanks. So when we say about the phase shift of a pole or zero, should we always converter it to the standard form? \$\endgroup\$ – anhnha Dec 15 '17 at 2:08
  • 1
    \$\begingroup\$ Writing transfer functions in a low-entropy form is the key to understand their asymptotic response in magnitude and phase. \$\endgroup\$ – Verbal Kint Dec 15 '17 at 6:30

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