EE newbie here.
I am trying to put an additional op-amp circuit onto a crowded half-sized "perma-proto" breadboard; I have no room remaining on the centerline to mount a DIP package.
What I do have is a dual op-amp in 8-pin DIP; I only need one of the amps, so on one side of the package only the +V pin is in use; I can straddle the DIP across the gap between the horizontals and the power rail, and the power pin will land in the right place.
Obviously in the interest of sanity I will clip the unused leads and put an insulator between the stubs and the power rail, and I know this is not an elegant solution or something I should be doing routinely.
But if I were to take a common 8-pin dual op-amp, and put all four pins on the right side (+V, inverting input, non inverting input, and output) onto a common +V rail, what would happen to the op-amp and the power rail?
I'm not asking for solutions to my layout problem; it's solved. I'm curious what the behavior of the part would be if connected in that way.