Let's assume I have 3 Leds which have forward voltage of 3.3v and current rating is 300mA. All the leds are in series and I have a power supply of 12v. when I series a resistor to limit current it draws much power.
Calculations:
Voltage through leds =\$3.3v*3=9.9v\$
voltage drop through resistor=\$12v-9.9v=2.1v\$
Resistor value for \$300mA =2.1v/0.3A=7\Omega\$
Power loss through resistor \$= 7*0.3=2.1W\$
I need to reduce this power loss.
Is there any way with MOSFET or BJT transistors?
I read this http://www.instructables.com/id/Power-LED-s---simplest-light-with-constant-current/ . But i don't understand how to calculate values. Here is the circuit diagram in above site.
I don't need exactly this. I need a proper way to do that.