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I want to build a constant current circuit of 317 mA using using a TIP 42C PNP transistor.

I am able to provide constant base current of 3.17 mA and the minimum value of beta of the transistor is 30.

I took beta as 100 for safety and still my collector current varies according to the load resistance connected to it.

Please tell me what I did wrong and how to make the circuit work.

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    \$\begingroup\$ Post a circuit diagram of your circuit, with proper designators and values. \$\endgroup\$ – MrGerber Jan 17 '18 at 11:04
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    \$\begingroup\$ You simply cannot and should not rely on the value of beta to multiply a current. Beta varies a lot and is unpredicatble. Use an opamp-based circuit as per Andy's answer. \$\endgroup\$ – Bimpelrekkie Jan 17 '18 at 11:30
  • \$\begingroup\$ The writeup mentions a TIP42C, but there is no such part in the schematic. Huh? What? Closing as unclear. \$\endgroup\$ – Olin Lathrop Jan 17 '18 at 12:17
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A simple PNP transistor fed with a constant base current is not going to function as what most people would describe as a constant current source. If beta is 30, the output current will be 95 mA and not 317 mA. Beta varies with temperature and saturation levels so it cannot be relied upon to be constant in a proper design.

A design that I have used a lot is here: -

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Taken from my answer here. Supporting text from that answer: -

Choose R1 to be low in value hence it won't drop too much voltage in sourcing current to the load. If you chose 1 ohm then to get 300 mA through the load, Vin would be 0.3 volts and the drop across R1 would also be 0.3 volts.

There are a variety of ideas about current sources here.

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  • \$\begingroup\$ Thnx Andy I saw the different current sources u just showed but i also need to know how they work too. can u help me with that? \$\endgroup\$ – Sarath Sasi kumar Jan 17 '18 at 11:56
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    \$\begingroup\$ The one in my answer - do you know how op-amps work? If not then you should do a bit of research on op-amps. It's beyond the scope of this site to side-issue a question (like yours) with a page of explanation how an op-amp works. If necessary ask a new question targetted at op-amps. \$\endgroup\$ – Andy aka Jan 17 '18 at 12:00
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my collector current varies according to the load resistance connected to it.

I should hope so.

Start with Ohm's Law, E = iR. Let's take i as .317 amps, and R as 100 ohms. Then the voltage will be 31.7 volts. Getting 31.7 volts from a 12 volt supply is a pretty good trick.

In fact, with a 10 ohm series resistor, and assuming a Vce of 1 volt or more (since for Vce lower than this the transistor is in saturation and the gain is MUCH less than 100), a 3.17 volt drop on the resistor and a 1 volt drop on the transistor only leave about 7.8 volts available for the load at the desired current. Again applying Ohm's Law says that for any resistance greater than about 24 ohms the current available will be less than the desired .317 and will vary with load resistance.

Other comments apply. Additionally, if the minimum gain of the transistor is 30, and you provide 3.17 mA of base current, by definition your collector current will be 30 x 3.17 mA, or 95 mA, rather than 317. What, exactly, do you mean by a "took the beta as 100 for safety"? Taking the beta as 100 is a) not guaranteed to happen in the real circuit (minimum is 30, right? Do you understand that "minimum" means that there is no guarantee that it will be larger, only that it will not be less?), and b) not going to provide consistent results, since as Andy aka has pointed out, beta varies with current and voltage. Modern data sheets don't go into this much, but in olden days they would typically provide graphs of typical variations.

Please tell me ... how to make the circuit work.

Sorry. Won't happen. You can increase V2 to at least 36 volts, and adjust the base drive with R1 to produce an appropriate current with a specific TIP42 at a specific load resistance, but neither of these things will provide a precision current level independent of load resistance. And also note that, if you do try this, for a load of 50 ohms the TIP42 will dissipate something like 5 watts, and for a 1 ohm load it will be about 10 watts, so unless you provide a decent heat sink (and I don't mean one of those little clip-ons, either) you'll get thermal effects ranging from increased current due to increased leakage to Letting the Magic Smoke Out.

Plus, at a 36 volt supply, you'll be right up against the 35 volt Vds rating of the 2N6659, so increasing R2 would be a very good idea.

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What you are doing in post #1 is called dangle-biasing. It is critically dependent on the gain of each transistor. the problem is that those gains vary from second to second with temperature, age, and the exact amount of collector or drain current.

If you search for 'constant current circuit schematic', you will see dozens of schematics; some with opamps, some with transistors, some with both. A common feature of all of them is some form of feedback to stabilize the output current value around something other than the output transistor's open circuit (intrinsic) gain.

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