# Power consumed by the Resistive load

I am really confused with the above problem. I can also solve the problem taking an AC supply across a 20ohm resistor and end up getting like

P = 100^2/20 = 500W

I am not able to digest the solution provided to me by my coaching institute and think that my solution is correct. Please help me with the above problem.

• add up 2 phasor voltages between R&Y using trig. then try again. The vague question means 100V Phase to neutral for each phase, not phase to phase – Tony Stewart Sunnyskyguy EE75 Jan 25 '18 at 20:52
• Am I correct in thinking that the calculation assumes a neutral connection at the star point when the schematic doesn't show one? This would change the result. – Transistor Jan 25 '18 at 21:03
• No further comments on your question. I think your answer is correct for the schematic given. – Transistor Jan 25 '18 at 23:25

The written solution to this problem will only be "correct" if a neutral line was present because then you can see that each load resistor will receive a phase voltage of 100/$\sqrt3$ = 57.74 volts and, using voltage squared divided by resistance for power, you get 333.33 watts per resistor making 666.66 wats in total.