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I am a programmer but new to electronics and trying to combine voltage two DC voltages. This works when I use two separate batteries i.e. I can use two 9v batteries and connect them in series to get total of 18V power supply.

However when I try to do the same using the two 5V output from the power supply as in Solderless Breadboard with Power and I/O Breakout Board. It just stops working. What I did is connect positive from the 1st 5V output to negative of 2nd 5V output, and as soon as I do that the power supply stops working (may be it shorts). Can anyone tell what I am doing wrong? and if it is not possible then why?

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closed as unclear what you're asking by Olin Lathrop, Sparky256, DoxyLover, JRE, Bimpelrekkie Feb 13 '18 at 12:11

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • \$\begingroup\$ Which power input are you using, the jack or the USB? \$\endgroup\$ – Trevor_G Jan 28 '18 at 12:49
  • \$\begingroup\$ I am using two 5V jacks. one on right side and the one on left side. \$\endgroup\$ – user1589040 Jan 28 '18 at 12:52
  • \$\begingroup\$ You really need to show how you have this hooked up, the question is sort of unclear. Maybe post a picture. \$\endgroup\$ – Trevor_G Jan 28 '18 at 12:53
  • \$\begingroup\$ Sure. working on it. give me 10 mins \$\endgroup\$ – user1589040 Jan 28 '18 at 12:53
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    \$\begingroup\$ It looks highly likely that input and output share a common ground, so you're shorting them out by trying to connect them in series. \$\endgroup\$ – Finbarr Jan 28 '18 at 13:05
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There are probably a 5V and 3.3V voltage regulator on your module. It means that both 5V power supplies on either side of the module are the output of the 5V regulator (same for 3.3V power jacks). So you cannot connect them in series to get 10V.

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    \$\begingroup\$ In layman terms, you mean that even thought both says 5V each, they both are internally connected (and not two separate/isolated ) and hence it is shorting ? If so, will it work if I replace this with another power supply providing two isolated outputs ? \$\endgroup\$ – user1589040 Jan 28 '18 at 13:10
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    \$\begingroup\$ @user1589040 you would need two of those breadboards to do what you want. Though even that will not work if you use the USB ports from the same source. \$\endgroup\$ – Trevor_G Jan 28 '18 at 13:18
  • \$\begingroup\$ @Trevor_G: You mean I will need two separate power supply units as show in the image on same breadboard OR I can sum the two 5V outputs of one power supply using two separate breadboards ? Sorry, if these r silly questions. \$\endgroup\$ – user1589040 Jan 28 '18 at 13:21
  • \$\begingroup\$ @user1589040 I mean if you had two breadboards each powered from it's own wallwart, you could hook them up and put the rails in series as you imagine. Though not sure the breadboard connections will allow you to fudge that. \$\endgroup\$ – Trevor_G Jan 28 '18 at 13:24
  • \$\begingroup\$ Yes. got it.... \$\endgroup\$ – user1589040 Jan 28 '18 at 13:31
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There is one 5V regulator and one 3V regulator on this module (the two identical parts with 3 pins on the left and one large pin on the right, between the yellow jumper terminals). So you are basicaly shorting the 5V output. You can't even put in serie the 5V with the 3V, because they are regulators on a same power supply, not power supplies themselves. I'm not sure it's even possible to put in serie from separate PSUs with these regulators... because they will regulate to 5V or 3V.

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