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I collected experimental data of input and output characteristics of a BJT NPN in Common Emitter configuration. I need to find the right function to fit the Ic vs Vce, but I'm not finding it. I've used the Shockley Equation with no luck. I have tried the Early model and it worked fine on the linear region, but I need to fit the whole curve. Could you help me finding the right formula? Thanks, Alberto.

Note: this is the function I've used with no success.

Ic = a+bx+c(1-exp((x/(d*e))) Where x is Vce

Update: My bibliography is Jacob Millman's Analog and Digital Circuits.

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    \$\begingroup\$ I suggest that you look at how transistor models used in circuit simulators like Pspice look like. Google for "BSIM" or "MEXTRAM" and have a look at how insanely complex these models are. The Shockley equation is more like a "first order" approach to the real behavior. Regarding fitting a model to the measurements, there are engineers that have this as their day job. It is complex. I don't believe you can expect the Shockley equation to fit the complete behavior of a BJT. \$\endgroup\$ – Bimpelrekkie Feb 23 '18 at 12:30
  • \$\begingroup\$ How far out was reality from theory? Show the discepancies if you want a complete answer. \$\endgroup\$ – Andy aka Feb 23 '18 at 13:10
  • \$\begingroup\$ You can find the expression for Vce as a function of Ic/Ib on the following editions of Millman's books: Electronic Devices and Circuits,"Voltages as functions of currents", p. 250 and Integrated Electronics, p. 148. Perhaps you can fit the logarithmic function to the inverted data. (Edit: now that I think of it, that model does not account for the Early effect). \$\endgroup\$ – Sredni Vashtar Feb 25 '18 at 21:32
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There are books on the subject of extracting parameters for BJTs from experimental test setups. What you do depends entirely on the parameter of interest at the time. And that depends upon the model. (There are more than a few.)

In the CE configuration, the BJT is in active mode. So on the surface it might seem that you can just use:

$$I_\text{C}=I_\text{SAT}\cdot\left(e^{V_\text{BE}\over n\cdot V_T}-1\right)$$

But, unfortunately, there are three horribly glaring holes in this active mode model. (At least three. Someone else will certainly point out my errors and add another few.) One of them is that \$I_\text{SAT}\$ is a function and not a constant. And the other is the Early Effect, which is unaccounted there. And a third is \$\beta\$, which of course is also a function and not a constant (and if you made a more sophisticated model based on 3D integrals and design details would itself no longer be needed.)

Here's an example of the dependence of \$I_\text{SAT}\$ on temperature:

$$I_\text{SAT}\left(T\right)=I_{\text{SAT}_{T_{nom}}}\cdot\left[\left(\frac{T}{T_{nom}}\right)^{3}e^{\frac{E_\text{g}}{k}\cdot\frac{T-T_{nom}}{T\cdot T_{nom}}}\right]$$

Note that \$E_\text{g}\$ is the effective energy gap (in eV) and \$k\$ is Boltzmann's constant (in appropriate units.) \$T_{nom}\$ is the temperature at which the equation was calibrated, of course, and \$I_{\text{SAT}_{T_{nom}}}\$ is the extrapolated saturation current at that calibration temperature.

The power of 3 used in the equation above is actually a problem, because of the temperature dependence of diffusivity, \$\frac{k T}{q} \mu_T\$. And even that, itself, ignores the bandgap narrowing caused by heavy doping. In practice, the power of 3 is itself turned into a model parameter.

Here is a curve that you would need to be able to approximate accurately for any given BJT (which still is just the BJT outside of a circuit and where you still need to develop something for the Early Effect.) Taken from Figure 2.15 from Ian Getreu's "Modeling The Bipolar Transistor":

enter image description here

In Region I, the decline in \$\beta\$ is due to three components which can be ignored in the other regions but cannot be ignored with low currents involved. These are:

  1. The formation of emitter-base surface channels (which can be reduced by the careful application of processing/manufacturing); and,
  2. The recombination of surface carriers (which also can be reduced by the careful application of processing/manufacturing, but still remains a dominant part of the problem); and,
  3. The recombination of carriers in the emitter-base space-charge layer.

All three of these have similar variations with the base-emitter voltage so that you wind up with something akin to the following typical component equations. (These are showing \$I_\text{B}\$ and not \$I_\text{C}\$, but this just means that the value of \$I_\text{SAT}\$ in the following equations isn't taken to be the same one discussed for \$I_\text{C}\$ -- keep in mind that \$I_\text{SAT}\$ is just a projected y-axis intercept and that concept can be applied equally well in a variety of contexts related to currents):

$$\begin{align*} I_{\text{B}_{channel}}&=I_{\text{SAT}_{channel}}\cdot\left(e^\frac{V_\text{BE}}{4\cdot V_T}-1\right)\\\\ I_{\text{B}_{surface}}&=I_{\text{SAT}_{surface}}\cdot\left(e^\frac{V_\text{BE}}{2\cdot V_T}-1\right)\\\\ I_{\text{B}_{space-charge}}&=I_{\text{SAT}_{space-charge}}\cdot\left(e^\frac{V_\text{BE}}{2\cdot V_T}-1\right) \end{align*}$$

Although summed exponentials are not exactly equivalent to any single resulting equivalent exponential, it is practical (and done) to combine the above into a single modeled exponential that uses \$\eta_\text{EL}\$ values often close to 2:

$$\begin{align*} I_{\text{B}_{summed}}&=I_{\text{SAT}_{summed}}\cdot\left(e^\frac{V_\text{BE}}{\eta_{\text{EL}}\cdot V_T}-1\right) \end{align*}$$

For most BJTs, the above equation can be made to approximate the reality well enough for practical purposes (and it sums into the usual current equations.)

In Region III, the injection of minority carriers into the base region starts becoming increasingly important in comparison against the majority carrier concentrations. Because the space-charge neutrality is maintained in the base, the majority concentration has to increase by the same amount.

The finding is:

$$\begin{align*} I_{\text{C}_{high-I_\text{C}}}&\propto e^\frac{V_\text{BE}}{2\cdot V_T} \end{align*}$$

The other factor in Region III is, of course, an 'Ohmic resistance' and is already modeled as \$r_c\$ so it isn't included above.

A model constant is usually applied to the above equation and the resulting term then appears in the divisor used for the usual model saturation current equation.

The upshot for Region III is:

  1. The increasing importance of the injected minority carriers into the base; and,
  2. Ohmic resistance.

And so far, we're just talking about one part of one quadrant of operation -- the active mode for your CE amplifier.

As I said, there are books on the topic. Whole product lines developed, with lots of software, to do this. (I own two working instruments from Tektronix STS now-defunct product line and several others from other manufacturers that are designed for the purpose of extracting parameters and providing charts.)

I don't want to discourage you from creating useful models of actual devices for the purposes of a real circuit that depends upon them. Tektronix made products that were based upon knowing more about BJTs than others and pushing the absolute limits of those devices in circuits that did actually depend upon device-selection for behavior. I've developed LED standard lamps by throwing away more than 99% of them and just keeping a few that "worked well" for the purpose.

Most people just design their circuits to "not overly depend" upon a specific model behavior, though. So you really need a reason to push like this. I think that's part of why you don't see a lot on the web about the subject.

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  • \$\begingroup\$ Thanks for the detailed description. My experiment wasn't a necessity of mine but it is an experiment we have to work on following the laboratory course in a degree in Physics. Talking with the teacher, he has said we have to watch only the Early Effect and don't mind the first part of the curve. He also suggested to fit the curve with the Shockley Equation and then the active region with the Early Equation. \$\endgroup\$ – Alberto Perro Feb 24 '18 at 10:40
  • \$\begingroup\$ @AlbertoPerro Are you still in need of a way of estimating the Early Effect? (I'm pretty certain you already know how to estimate the saturation current by just drawing a line back to the y-axis on a log scale graph.) \$\endgroup\$ – jonk Feb 24 '18 at 20:44
  • \$\begingroup\$ Yes, with the Early Effect is a simple linear fit. Thanks \$\endgroup\$ – Alberto Perro Feb 25 '18 at 22:42
  • \$\begingroup\$ @AlbertoPerro Okay. So everything is good. Just wanted to be sure you had what you felt you needed for now. Thanks for the update. \$\endgroup\$ – jonk Feb 25 '18 at 22:50

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