I'm a newbie who just started studying EE and I'm presented with this problem as shown here.
I have to calculate all currents, meaning I1, I2, I3, I4, I5. I have the value of each resistor and the value of the current source I, which is 1A.
Now, for I1 I did the following: I added R2 and R3 (I think it's doable because there's an empty wire between them and R4...) and then I multiplied that value I got with R1 and divided it by the sum of those 2 components...
Basically it was 30 * 20 / 50 and I got 12 ohms.
Now I use the formula for calculating current. I1 = I * R4 / (12 + R4) So now I1 is 0.6A. This value is correct.
To get I2 I can use Kirchoff's current law and I get that 1 = 0,6 + I2, from which I get that I2 = 0.4. So far so good.
Now, how do I go about calculating the rest?
Since I5 is an empty wire, can I just say that the current there is the same as I2?
According to the solutions presented I5 is 0,4 too, I3 is -0,4 and I4 is 0. Now I know that I = I1 + I2 + ... + In... so the sum of all these Is must be 1. But why isn't I4 0.4 and I5 0?
What's the thinking behind it? I'm just not very clear as to how this works.