I was trying to solve the above problem. As I have done many similar problems, I attempted it in the following way
But I was shocked when I checked the solution given in my workbook.
Please help me to understand this problem.
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The coupling of other phases tends to oppose to induction of each phase slightly. You are close.
answered Feb 26 '18 at 18:04
Tony Stewart Sunnyskyguy EE75Tony Stewart Sunnyskyguy EE75
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\$\begingroup\$ Sir, why my method is wrong ? Is it a special case ? \$\endgroup\$ – Nikhil Kashyap Feb 26 '18 at 18:08
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2\$\begingroup\$ You neglected phase shift of other 2 currents coupled into each at +\- 120 deg \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Feb 26 '18 at 18:13
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1\$\begingroup\$ Yes, I assumed Ia =Ib = Ic. I will go through the derivation once again. \$\endgroup\$ – Nikhil Kashyap Feb 26 '18 at 18:39
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\$\begingroup\$ Yes it is I(t) for ABC \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Feb 26 '18 at 18:42
