0
\$\begingroup\$

enter image description here

I was trying to solve the above problem. As I have done many similar problems, I attempted it in the following way

enter image description here

But I was shocked when I checked the solution given in my workbook.

enter image description here

enter image description here

Please help me to understand this problem.

\$\endgroup\$
1
\$\begingroup\$

The coupling of other phases tends to oppose to induction of each phase slightly. You are close.

| improve this answer | |
\$\endgroup\$
  • \$\begingroup\$ Sir, why my method is wrong ? Is it a special case ? \$\endgroup\$ – Nikhil Kashyap Feb 26 '18 at 18:08
  • 2
    \$\begingroup\$ You neglected phase shift of other 2 currents coupled into each at +\- 120 deg \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Feb 26 '18 at 18:13
  • 1
    \$\begingroup\$ Yes, I assumed Ia =Ib = Ic. I will go through the derivation once again. \$\endgroup\$ – Nikhil Kashyap Feb 26 '18 at 18:39
  • \$\begingroup\$ Yes it is I(t) for ABC \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Feb 26 '18 at 18:42

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.