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QRP Radio transmitter circuit.

I am trying to understand how this circuit operates.

I understand how the circuit works on the right side of the transistor, but the oscillation stage with the crystal confuses me.

It appears that the crystal has no feedback from the output of the oscillator. I researched this and found out that the collector-base capacitance of the transistor provides a feedback path, but wouldn’t that only give a 90° phase shift instead of the 180° phase shift required for positive feedback?

I have seen similar circuits where a variable capacitor is included with the crystal to adjust frequency. Would that give the phase shift for the remaining 90°?

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    \$\begingroup\$ Where did you discover this schematic? \$\endgroup\$
    – Andy aka
    Mar 8, 2018 at 22:02
  • \$\begingroup\$ I don’t really remember where, it was on an older ham radio website, I believe. \$\endgroup\$
    – Ant. K.
    Mar 8, 2018 at 22:41

6 Answers 6

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Yes, it could oscillate, but in a SPICE simulator, it didn't. Not quite. A few component changes did start oscillations. The 7MHz crystal equivalent circuit is a guess (C1, L2, R5, C2): oscillating transmitter
The base-to-emitter capacitance of the 2N2222 is large enough that this is a Colpitts-type oscillator.

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    \$\begingroup\$ Spice does not understand old low frequency crystals that can self-oscillate, up to about 20 MHZ. \$\endgroup\$
    – user105652
    Mar 8, 2018 at 21:45
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    \$\begingroup\$ The colpitts idea sounds feasible +1 \$\endgroup\$
    – Andy aka
    Mar 8, 2018 at 22:04
  • \$\begingroup\$ Oscillates a little below crystal parallel resonance frequency, (where L2,R5,C2 series branch has a net inductance) and a little above crystal series resonant frequency (where L2 & C2 reactances are equal). For crystals, that's a fairly small frequency span. \$\endgroup\$
    – glen_geek
    Mar 8, 2018 at 23:03
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    \$\begingroup\$ A clapp oscillator is probably what it is. \$\endgroup\$
    – Andy aka
    Mar 8, 2018 at 23:13
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This question has quite interesting answer history - at least for +10k rep members who can see the whole history. But there's done some reductions => I think that now here's also room for my answer:

At first: The crystal can be any reactive impedance from nearly zero ohms to very high number of ohms. The reactance can be as well inductive as capacitive and the losses are extremely low when compared to practical LC-circuits. And all those reactance values are found from very narrow frequency band around the stamped frequency of the crystal.

=> It's well possible that at some frequency the CB capacitance of the transistor and the crystal form together a phase inverting voltage divider which attenuates less than the amplifier amplifies => oscillation.

In practice also the input impedance of the transistor must be taken into the account => exact full 180 degrees phase shift in the feedback route doesn't happen. But the amp also doesn't cause exact 180 degrees phase shift, because the loading is partially reactive => It's still well possible that oscillation happens.

There's no need to try to classify this oscillator "is it hartley or colpitts or or clapp or some other well known type". Those well-known LC oscillators were designed to make oscillations possible and controllable with low gain triode electron tubes. We have here a high gain transistor and the crystal. But if someone forced me to name one old electron tube oscillator that can be considered to be the grandma of this circuit, I would write TGTP (=tuned grid, tuned plate).

ADD: Radio circuit engineers do amplifier stability calculations. It's not uncommon to find that amplifier is unstable due the reactances of input signal source, load reactance and the internal feedback of the transistor. Microwave oscillators are often constructed as unstable amplifiers. In place of the crystal there's a high-Q microwave resonator.

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Draw the circuit like this. The inverting amplifier inverts between base and collector.

schematic

simulate this circuit – Schematic created using CircuitLab

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The missing knowledge is that: A cap's current leads it's voltage by 90 degrees. An inductor's current lags it's voltage by 90 degrees.

When they are in series, the current is the same for both, so the junction voltage is 180 degrees at resonance.Thats also why a series resonant circuit appears as a short.

Now reason out the parallel resonance circuit, where the two elements both have the same voltage.

As mentioned above a crystal is a series or parallel resonance circuit.

Yes the transistor's collector-base capacitance provides driving energy.

BTW: Many FETs oscillate due to gate inductance and drain to gate capacitance. Often at a frequency so high, it is Only noticed as a DC shift when you wave your hand over it.

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    \$\begingroup\$ It's worth mentioning that actual inductor/capacitor phase shifts depend on the feeding and load impedances, they only approach +/- 90 degrees. Consider them as RC or RL low pass or high pass filters, with the phase shift depending on both R and C or L! \$\endgroup\$ Mar 9, 2018 at 11:52
  • \$\begingroup\$ This is only true if you are considering the parasitic resistance. Capacitor and Inductors are 90° phase shift between current and voltage, independent of all external resistance. When capacitor and inductor are in series they have exactly the same current at all times. (When much less than the speed of light) \$\endgroup\$ Mar 11, 2018 at 4:59
  • \$\begingroup\$ No it's true regardless of parasitics. Otherwise, an RC low pass filter would always have 90 degree phase shift for example. They contribute a reactance, but that doesnt actually mean they have 90 degree phase shift across them. If this wasnt the case, an LC resonant circuit would have no dependence on source and load impedance, but in fact the Q of the circuit depends heavily on them. The circuit wont really 'resonate' with values of Rs or RL that are of the magnitude of the reactance or the inductor or capacitor. \$\endgroup\$ Mar 11, 2018 at 14:47
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If you temporarily remove the crystal, you should see that the circuit will oscillate at a frequency primarily determined by RFC1 and C1. The only thing the crystal does, is stabilize the oscillation frequency!

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If you put a pulse voltage source in the circuit, it will work on spice too.

In real world there are a lot of signals that can cause the oscillator to start up.

But in spice you have to add a source of signal to let the oscillator to start up.

This can be done for example by changing the oscillator input voltage for a short duration of time like 1 uS.

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