I understand the use of diodes as switches or "clamp circuits", however I needed a little clarification in this diagram, taken from the site https://www3.nd.edu/~lemmon/courses/ee224/web-manual/web-manual/lab5/node9.html
I understand that when Vin>5 V, the top diode to the power supply is forward biased, and ~shorted, and when Vin< 5 V the top diode is reverse and open. However is the bottom diode to R2 and ground not forward biased in both cases? I don't quite see how that arm is always an open circuit if we don't know Vout. Thanks!