What happens if one of the poles of the primary winding of a transformer is connected to one of the poles of the secondary winding of said transformer, such that electricity

  1. leaves the power source,
  2. enters one of the poles of the primary winding,
  3. passes through the primary winding,
  4. exits the primary winding at its other pole,
  5. passes through the connecting wire to one pole of the secondary winding,
  6. passes through the secondary winding,
  7. exits the secondary winding at its other pole,
  8. passes through a resistor of some sort (to keep this from just being a short circuit),
  9. returns to the power source?

Yes, I have read this question. That one describes an isolation transformer shorted at each end, so that electricity can simply bypass the transformer; my question is about a transformer wired in such a way that electricity is forced to pass through both windings, one after the other.

  • 2
    \$\begingroup\$ Can you provide a schematic illustrating what you described? \$\endgroup\$ – AlmostDone Mar 15 '18 at 0:50
  • 2
    \$\begingroup\$ Depending on primary to secondary phasing, what I think you described is known as a buck or boost transformer; it either subtracts or adds voltage from/to the primary source. \$\endgroup\$ – AlmostDone Mar 15 '18 at 0:51
  • 6
    \$\begingroup\$ Congratulations, you've invented the autotransformer. \$\endgroup\$ – Ian Bland Mar 15 '18 at 1:04
  • 3
    \$\begingroup\$ Connecting the two windings of a transformer in series would give you a crude version of an autotransformer. \$\endgroup\$ – Solomon Slow Mar 15 '18 at 1:06
  • 2
    \$\begingroup\$ @Sean. Please provide a diagram or you will get no written answer. We think we know of what you speak, but we are not sure. \$\endgroup\$ – user105652 Mar 15 '18 at 3:08

What you described sounds like one of the two transformer-as-inductor connections shown below and in How do I use a transformer as an inductor?.

It could also be an autotransformer boost or buck connection shown below.

Dots designate start of winding.

enter image description here .

  • 1
    \$\begingroup\$ Ah, thanx - that clears it up. What I was thinking of was either of the two diagrams on the left. So, basically, I'd just have a big inductor? \$\endgroup\$ – Sean Mar 16 '18 at 19:31
  • 1
    \$\begingroup\$ Yes that is what you have. \$\endgroup\$ – Charles Cowie Mar 16 '18 at 20:19

Not the answer you're looking for? Browse other questions tagged or ask your own question.