Hi! I came across this question in lab, and it's been several years since I last done analog circuits. The voltage gain here in this op-amp should be 0.707 (-3db cut-off), and it asks us to find the capacitance. The way I see it is
V_in/(1000 + 1/jwC) = -V_out/10000
And after performing some simple arithmetic, we will be able to find the capacitance. However, the answer that I'm getting is wrong, so could anyone please show me the workings of how this should be done.
Much thanks fellas!