0
\$\begingroup\$

I need to find the voltage on the diode, ie the potential difference between NODE1 and NODE2. I thought of using Thevenin or knits, would anyone know a better way to analyze this circuit?

schematic

simulate this circuit – Schematic created using CircuitLab

\$\endgroup\$
4
\$\begingroup\$

Remove the diode, you have 2 voltage dividers connected to DC sources. There's 4V over R2, + at NODE1. There's 6V over R4 + at NODE2.

Put the diode back. It has 2V reverse bias, it affects nothing except some leakage. In datasheet the leakage is 10uA at 1000V reverse voltage. It cannot be more with 2V reverse. The exact leakage can only be estimated with some diode model or measured in a practical circuit.

To stay in truth, this reasoning utilized Thevenin's equivalents of the voltage division circuits. You can continue with them if you assume some leakage current, for ex. just that 10uA or find a better estimate.

If you assume that the leakage through D1 is somewhere between 0 and 10uA, you get the limits for the voltage between NODE1 and NODE2. The upper limit is that 2V assuming the leakage =0.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.