0
\$\begingroup\$

I have built the following AM radio circuit : enter image description here

I was able to pick several radio stations. I fixed the variable capacitor so that I can only hear the 1230 kHz station which I identified from the FCC call letter. I connected the antenna directly to my oscilloscope and obtained the following FFT:enter image description here

This shows all the stations received by the antenna. However, I connected my oscilloscope between the diode and the variable capacitor in reference to the circuit ground and obtained the FFT: enter image description here

How is it possible that the largest peak was not attenuated while small peaks surrounding the station I hear were attenuated even though I can't hear the largest peak frequency? and why is the voltage increased?

\$\endgroup\$
3
  • 2
    \$\begingroup\$ looking at the plots I'd say that it's tuned to 950Khz, not 1230 \$\endgroup\$ Commented Mar 25, 2018 at 5:33
  • \$\begingroup\$ it could be that the largest peak is not an AM radio station. \$\endgroup\$ Commented Mar 25, 2018 at 5:35
  • \$\begingroup\$ Looks like adding the scope probe re-tuned the antenna circuit from 1230 to 900 kHz. \$\endgroup\$
    – user16324
    Commented Mar 25, 2018 at 10:08

1 Answer 1

2
\$\begingroup\$

Try putting the variable capacitor in parallel with the coil and you will better results. Having the variable capacitor in series with the antenna just alters the electrical length of the antenna. If memory serves me correctly (i'm an old guy..its been a while) when the variable capacitor is in parallel with the coil will create a resonant circuit that will allow you capture radio stations.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.