# Reducing voltage/current of AC circuit with makeshift bi-polar capacitor

WARNING! To others reading this question: This circuit uses high voltage. DO NOT mess with 220V/110V unless you know what you're doing and know the risks (electrocution and death, mainly)

Now that that's out of way...

Hello everyone, I'll try to be as brief as possible: I have a heating element taken from a 220V hot plate and connected like so:

Components:
Vs: 220V (RMS) 50Hz sine AC (from wall outlet)
U1: Bog standard DIAC-TRIC dimmer
R1: The heating element, 100 Ohms in room temperature (assumed more when hot)
R2: A very small incandescent light bulb, also taken from the hot plate, I assume its current is negligible

I need to slightly reduce the current of the heating element. I thought about a non polarized 100V 100uF capacitor but I don't have one. I do have 50V 1000uF polarized capacitors, so, my first question: If identical capacitors in series have their max allowable voltages added up but their capacity divided by the number of capacitors, AND, if 2 identical polarized capacitors connected in series with reverse polarity make a non polarized capacitor with half the capacity (reference), then, will connecting eight 50V 1000uF polarized capacitors back to back create the equivalent of a single 200V 125uF bi-polar capacitor?

The new schematic:

New components:
C1 - C8: Radial aluminum electrolytic polarized 50V 1000uF capacitors

So if my calculations are correct, when the dimmer is at full and the element is at room temperature, the capacitors will measure 63V at peak amplitude and will reduce the RMS current by 447mA (2.2A without the capacitors, 1.753A with them).

Second question: Is everything I wrote correct? Or did I accidentally build the equivalent of a hydrogen bomb that will destroy my house, neighborhood, and everyone I've ever known and loved??

• You know you'll be adding a lot of impedance to the circuit by introducing all those capacitors don't you?
– MCG
Commented Mar 27, 2018 at 10:19
• Better to just control the dimmer range, surely?
– user16324
Commented Mar 27, 2018 at 10:42
• Why do you need to reduce the current of the heating element, when it's already connected to a device for reducing its power? Is it necessary, or will your capacitors be sufficient, for the problem you actually have, rather than the one you state? Commented Mar 27, 2018 at 10:46
• MCG: Is there a downside to this impedance? Brian Drummond: The dimmer is a built product, not a circuit by me and I don't want to modify it. Neil_UK: I want to reduce the whole range, I.E. I want a lower current at both the minimum and the maximum values of the dimmer. I hope I managed to explain it correctly now. Commented Mar 27, 2018 at 11:29
• Why was my question downvoted? Did I do something wrong? Please explain my mistakes to me so that I can avoid making them again. Commented Mar 27, 2018 at 11:43