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I have found the current right but I thought 22V-2.2k(4.84mA)-0.7 would be equal to V0(or 2.2k(4.84mA), voltage from lower branch- both are equal and so no inconsistency), why is my logic wrong and where did 1.2k come from?

enter image description here

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  • \$\begingroup\$ That's a typo followed by calculation mistake. It should be \$2.2\,k\Omega\$ instead of \$1.2\,k\Omega\$ \$\endgroup\$ – nidhin Mar 27 '18 at 11:45
  • \$\begingroup\$ so the answer is wrong as well? it should also be 2.2k(4.84mA)=10.65V? @nidhin \$\endgroup\$ – J. Doe Mar 27 '18 at 11:47
  • \$\begingroup\$ Yes. If the schematic is correct, then the answer should be 10.648 V \$\endgroup\$ – nidhin Mar 27 '18 at 11:49
  • \$\begingroup\$ Or the value of lower branch resistor might be 1.2 kΩ \$\endgroup\$ – Dhans Mar 27 '18 at 11:54
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nidhin was right, in your calculation you have for the second resistor 1.2kOhm instead of 2.2kOhm I've calculated it for you here.

enter image description here

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