A popular standard for the transmission of digital audio between audio devices has been the AES3 standard (also known as S/PDIF). The standard sends stereo PCM audio and of often found in consumer electronics. The standard specifies multiple interconnection types with RCA coaxial cables and optical TOSLINK being two most popular.

Commonly in audio manuals, it is commonly noted that the optical TOSLINK provides a superior connection due to the superior aspects of optical cables in general. I understand the physical medium of optical fibers are less prone to noise and possess higher theoretical bandwidth. Personally, I have never noticed a difference between the two.

I want to ask, within the scope of digital audio transmission, it is their any observable or measurable differences between the two cables? If not in audio fidelity, is there a difference in transmission quality? Is TOSLINK more than an overpriced cable?


RCA Cable RCA connectors are cheaper and more universally available.

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    \$\begingroup\$ More to the point, if it's digital and the cable is good enough to transmit the data at all, what does it matter what the cable's made of? \$\endgroup\$ Mar 29, 2018 at 2:25
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    \$\begingroup\$ I think for mixer consoles it was preferred for low latency. TOshiba offered 6MBps in NRZ up to 20Mbps TODX2097A(F) \$\endgroup\$ Mar 29, 2018 at 3:06
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    \$\begingroup\$ TODX2402(F) provides full-duplex 250 Mb/s transmission. But compared to RCA lossless and same as CD/DVD recording without noise \$\endgroup\$ Mar 29, 2018 at 3:12
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    \$\begingroup\$ Well, I can send Dolby or THX surround sound streams directly to my speakers over TOSLINK. With RCA I'm limited to Stereo sound... (well, ok, I can provide separate connections from my sound-card for the other speakers, but that's more than the L and R channels that you think of with RCA) \$\endgroup\$
    – Baldrickk
    Mar 29, 2018 at 14:39
  • \$\begingroup\$ The main advantage, as I understand it, is Rule of Cool. You can say stuff about ground loops and speed but I can't imagine any origin story other than some engineer or middle manager saying "hey, we could use this fancy new optical fiber technology for this, let's do that, it'll be cool!". And I suppose they weren't wrong! \$\endgroup\$
    – Hearth
    Oct 20, 2022 at 19:33

4 Answers 4


In addition to the answer of TimB, there is another advantage of this optical communication.

With RCA, the two networks connected have to be referenced to each other. In the case of optical, there is galvanic isolation between the two. As a result, there might be less issues with ground loops, networks can remain isolated, etc. It also means that the grounds can't act as a big antenna which might make it easier to get low noise in the system as a whole.

And additional disadvantage of the RCA connectors is in the ground connection. If you look at most modern connectors, you will see that the ground connection is made first. As a result, the two circuits being connected are first pulled to the same potential, and then the actual data is connected. If data is connected first, this still happens - but the currents to do so now have to flow through your likely far more sensitive digital receiver circuits. In the RCA connectors, the first connection is the center pin that carries the data. For this reason I have often been told that you should always connect the RCA connectors first, before connecting the entire system to the mains voltage - or use the ground lug that some of these devices have to reference the system to mains earth at all times. Needless to say, this issue is not present in the optical versions, and thus they are more suited to hot-plugging.


I want to ask, within the scope of digital audio transmission, it is their any observable or measurable differences between the two cables?

Actually, yes.


Optical fiber isn't conductive, so it solves ground loops, hum/buzz issues and any is insensitive to RF interference. Coax can also be isolated with a transformer, however this adds to the cost and is uncommon in consumer equipment. A quick test with a multimeter between digital RCA ground and any other RCA ground will reveal if there is transformer isolation or not.

This really matters for cable TV boxes which are connected to the cable's ground, as this tends to create annoying ground loops.


The majority of optical transceivers on the market will have enough bandwidth for 24bits/96kHz, but only a few will pass 24/192k, and none pass 384k. If you want to know which one you got, make a test. That's rather binary: it works or it does't. Of course you can buy optical transceivers with much higher bandwidth (for ethernet, among other things), but you won't find these in audio gear.

Coax has no trouble with bandwidth, it'll pass 384k with no trouble, whether it will sound better is left as an exercise for the marketing department.

Whether 192k is a marketing gimmick or useful is an interesting question, but if you want to use it and your optical reveiver doesn't support it then you'll have to use coax.


Plastic optical fiber is cheap. Count on 1dB/m attenuation. This isn't high-quality glass-core telecom fiber with 1-2dB/km loss! This doesn't matter for a 1m long fiber in your home cinema, but if you need a 100 meter run, coax will be the only option. 75R TV antenna coax is fine. Or better fiber, but not plastic. Connectors are, of course, not compatible.

(Note 1dB/m is for the digital signal, not the analog audio. If the digital signal is too attenuated the receiver won't be able to decode it, or errors will occur).

Bit Error Rate

Barring a major issue, all the bits will be there with both systems (I checked). BER is not an issue in practice. Anyone who talks about bit errors in SPDIF has something to sell, usually an expensive gimmick to solve a non-existent problem. Also SPDIF includes error-checking, so the receiver will mask any errors.


Optical receivers add a lot more jitter (in the ns range) than well-implemented coaxial.

If the coax implementation is botched (not enough bandwidth extension on the low end, violation of 75R impedance, high intersymbol interference, etc) it can also add jitter.

This only matters if your DAC at the receiving end doesn't implement proper clock recovery (ie, WM8805, ESS DACs, or other FIFO-based systems). If it does it properly, there will be no measurable difference, and good luck hearing anything in a double blind test. If the receiver doesn't clean jitter properly then you'll have audible differences between cables. This is a "receiver not doing its job" problem, not a cable problem.


SPDIF embeds the clock into the signal, so it must be recovered. This is done with a PLL synchronized with the incoming SPDIF transitions. The amount of jitter in the recovered clock depends on how much jitter is in the incoming signal transitions, and the ability of the PLL to reject it.

When a digital signal transitions, the important moment occurs when it passes through the logic level threshold of the receiver. At this point, the amount of jitter added is equal to the noise (or amount of error added into the signal) divided by the signal slew rate.

For example if a signal has a risetime of 10ns/V, and we add 10mV noise, this will shift the logic level transition in time by 100ps.

TOSLINK receivers have a lot more random noise than what would be added by a coax (the photodiode signal is weak and must be amplified), but this isn't the main cause. It is actually band-limiting.

Coax SPDIF is usually AC-coupled with a cap or transformer-coupled. This adds a high-pass on top of the natural low-pass nature of any transmission medium. The result is a bandpass filter. If the pass band isn't large enough, this means past signal values will influence current values. See fig.5 in this article. Or here:

enter image description here

Longer periods of constant levels (1 or 0) will influence the levels on the next bits and move the transitions around in time. This adds data-dependent jitter. Both the high-pass and low-pass sides matter.

Optical adds more jitter because its noise is higher, and its passband is smaller than a properly implemented coax. For example, see this link. Jitter on 192k is very high (almost 1/3 of a bit time) but jitter on 48k is much lower, because the receiver doesn't have enough bandwidth for the 192k signal, so it acts as a lowpass, and the previous bits smear into the current bit (that's intersymbol interference). This is almost invisible on 48k because receiver bandwidth is sufficient for this sample rate, so intersymbol interference is much lower. I'm not sure the receiver used by this guy actually supports 192k, the waveform really looks bad and I doubt the decoder chip would find it palatable. But this illustrates bandwidth vs intersymbol interference well.

Most optical receivers datasheets will specify a few ns jitter.

The same can occur with a bad SPDIF coax, if it acts like a low pass filter. The highpass part of the transfer function also plays a part (read the article linked above). Same if the cable is long and impedance discontinuities cause reflections which corrupt the edges.

Note this only matters if the following circuitry doesn't reject it. So the end result is very implementation dependent. If the receiver is CS8416 and the DAC chip is very sensitive to jitter, it can be very audible. With more modern chips which use a digital PLL to reconstruct the clock, good luck hearing any difference! These work very well.

For example WM8805 runs the received data through a tiny FIFO and uses a Frac-N clock synthetizer to reconstruct the clock, whose frequency is updated once is a while. It is rather interesting to watch on the scope.

  • \$\begingroup\$ Could you provide some sources on the claim regarding jitter? I have not seen this statement before and would like to look into it further. \$\endgroup\$
    – Joren Vaes
    Mar 29, 2018 at 9:28
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    \$\begingroup\$ @JorenVaes I've added a few links. \$\endgroup\$
    – bobflux
    Mar 29, 2018 at 10:55
  • \$\begingroup\$ Coax can also be isolated with a transformer, however this adds to the cost and is uncommon in consumer equipment Are optocouplers a reasonable alternative? I know they are used in MIDI ports connected with copper, for example. \$\endgroup\$ Mar 29, 2018 at 14:27
  • \$\begingroup\$ @TobiaTesan the typical SPDIF output is 0.5-1Vpp and cap coupled so it won't have enough juice to power the LED in an opto. So you need a fast opto (>16Mbps) and an isolated supply for the input side... would cost more than a good transformer which isn't expensive, simply in consumer electronics every cent counts... \$\endgroup\$
    – bobflux
    Mar 29, 2018 at 15:58
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    \$\begingroup\$ @AaronD I hadn't even thought that the confusion would be possible, but I put your comment in the answer just in case ;) \$\endgroup\$
    – bobflux
    Mar 29, 2018 at 21:07

Fiber optic does not radiate electromagnetically, but more important is that is immune to electromagnetic interference that can cause data corruption on copper in extreme conditions. Such interference may come from the arcing of a switch being switched off under load, or can be generated by a motor under high load.

  • \$\begingroup\$ To add some anecdotal evidence to this, with cheap copper cables I have had the digital audio signal drop out for a second each time I turned the light switch on or off, due to interference induced in the cable. Swapping it for a plastic optical cable fixed the problem. So it doesn't even need to be extreme conditions to cause interference, if you're using suitably awful cables. \$\endgroup\$
    – Malvineous
    Apr 14, 2019 at 6:38

Well I bought a cheap co-axial digital cable and a cheap SPDIF optical lead and for sure the coax sounded dull and flat, I swapped to the optical cable and it was brighter and lively across the whole frequency range. So it is not all marketing hype, I have been involved in HiFi and Electronics professionally since leaving school over 40 years ago

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    \$\begingroup\$ Can you quantify what "dull and flat" and "brighter and lively" mean? Was there a difference in the frequency distribution of each signal? Are you able to suggest any reasons for why that may be? \$\endgroup\$
    – LeoR
    Mar 29, 2018 at 15:43
  • \$\begingroup\$ I did not have a spectrum analyser to hand but you can assume it sounded like there was a roll off at high frequencies and low ones \$\endgroup\$
    – code head
    Apr 3, 2018 at 11:28

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