I’m planning on using an MCP1700 to drop the voltage of a lithium polymer battery from 3.7 V to 3 V. The battery will be connected to the regulator via a charging circuit (https://www.sparkfun.com/products/10217). The data sheet for the regulator suggests a 1 µF capacitor on its input and output for stability. How important is this? I’m currently using a regulator without capacitors, and my device powers on and runs just fine.

Does it simply make the regulator less efficient, due to less stability and it having to “chase its tail” more?

What about on the input? Does the charger circuit take care of any needs?

The device it's going into is a Game Boy Advance which already regulates its voltage a bit (it’s used to being powered by AA batteries), so I was considering leaving the capacitors off.


5 Answers 5

The data sheet for the regulator suggests ... How important is this?

About as important as that your circuit work reliably.

Trying to second-guess datasheets is a bad idea. Unless the datasheet explains exactly what is going on and gives you guidance on different choices, the specifications are requirements, not options.

Only Microchip knows the limits of stability of the MCP1700. Their engineers have analyzed this over many cases of of current, headroom, output impedance, temperature, and other parameters. They have distilled the result of all this analysis down to a simple range of capacitance that need to be on the input and output for the device to reliably work. Why would you not follow that?

When you violate any specification in the datasheet, all remaining specifications become null and void. There is no longer any guarantee what the device will do. One or a few individual devices seeming to operate correctly at some limited combinations of current, dropout voltage, temperature, source impedance, output impedance, etc, is not useful evidence of anything.

Speaking in general, the input cap is to guarantee that the regulator sees some minimum impedance at certain frequencies. Ideally the input voltage has 0 impedance. Since that's not possible, they tell you the minimum input capacitance to put right by the regulator to guarantee the input impedance the design assumes.

The output capacitance is part of the overall feedback loop, so effects stability. The requirements vary considerably across regulators, especially LDOs like the MCP1700. Early LDOs were intended for tantalum capacitors on the output and actually relied on some minimum ESR (effective series resistance) of the cap. Others specify a range of capacitance, with both higher and lower being bad. One nice thing about the MCP1700 is that there is no minimum ESR requirement. You can connect a ceramic cap directly to its output. In fact, you need to.

Do what the datasheet says, else you're a test pilot.

  • 2
    \$\begingroup\$ Chiming in, you also can't rely on testing to get you out of trouble if you plan on manufacturing. Stepping away from the datasheet gets you into the marginal territory where batch variation starts to hurt you. It is entirely possible for Microchip to change the internal workings chip at any time and not mention it if the device stays within specifications. \$\endgroup\$
    – lod
    Commented Apr 9, 2018 at 2:25
  • \$\begingroup\$ Maybe the question should be "Is there ever any reason not to do what the datasheet indicates?" \$\endgroup\$ Commented Apr 9, 2018 at 13:53

You should follow the recommendations in the datasheet. If you don't, you risk oscillation. The regulator starts to oscillate - the output goes up and down. When I've had it happen, the regulator also got hot.

The datasheet of the MCP1700 recommends a 1uF capacitor on the ouput. This is a minimum. It also recommends the capacitor be located as close as possible to the regulator pins.

Often times you need to keep an eye on the internal resistance (equivalent series resistance =ESR) of the capacitor. Some will oscillate if the ESR is too high (or too low.). The MCP1700 appears to be fairly tolerant - the datasheet mentions using different types of capacitors that have large differences in ESR, and says they can all be used without problem.

It also recommends a capacitor on the input. The example circuit shows a 1uF, but doesn't go into any detail about it.


Regulators without the specified capacitors can oscillate, and not regulate properly. I've known it happen in a circuit built by a friend. The capacitors should be as close as possible to the regulator leads.


You might notice small oscillations, which aren't the best thing in a circuit.

PS: I really don't see a problem of using two 1 µF capacitors: they're not so big that it would cause problems at integrating them into the system. Also you can find them even as SMD and just solder them between the legs of the 1700 and the problem is solved.


I’m using a TLV755 LDO in a circuit I’ve been working on to boost the output of a supercapacitor to 3.3V as it is discharged.

The IC that it’s powering does some internal voltage regulation, and without the LDO, the circuit runs for about 45 minutes before the voltage drops too low to keep things running smoothly.

When I first introduced the LDO, I used the wrong capacitors, and it dropped the running time of my circuit to only 15 minutes. With the correct input and output bypass capacitors, the same LDO lets my application run for about 3 hours.

In the case of voltage regulation, the choice of bypass capacitor is crucial. Without this, voltage regulation might still work, but it is highly probable that it isn’t working nearly as efficiently as it could. The capacitors exist to keep the regulator from having to work as hard to provide a stable output. Without the proper capacitance, the regulator will be fighting against an unstable input, and as as a result it will function suboptimally and produce suboptimal output.

In my case, it was the difference between a 400% increase in efficiency and a 300% decrease.


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