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I would really appreciate some help here, I've spent a lot of time on this and can't get it right. Looking at datasheets and answers here actually made me even more confused...

I'm trying to control the gain of an audio source (300 mV pp) with the MCP42010 digipot as a voltage divider powered from a single supply of 5 V.

After I do that, I plan to pass the attenuated output through a buffer and sum it with another audio signal with a summing amplifier.

I understand that this IC is not the best candidate for audio (it is linear and does not have a zero crossing function) but I have it working nicely with my setup and need something working quickly. I'm OK with some minor zipper noise.

My problem is that I don't understand what is the "right" way to connect the signal to the pot: should I bias the signal before it enters the pot (on pin A) to 2.5 V? if so, what should the voltage on the other pin (B) of the pot be?

It looks like people say that you should not have DC voltage across the pot, so ground is not going to work.

schematic

simulate this circuit – Schematic created using CircuitLab

I also found this example, where they have another funky way of setting it up with two voltage dividers with resistors of different values on each side of the pot, something like this:

schematic

simulate this circuit

And in this example (page 18 figure 11) they bias the B pin of the pot to 2.5 V and the input is between positive and negative 2.5 V:

schematic

simulate this circuit

which I understand even less, since the pins on the pot can have maximum ratings of 0-5 V, so pin A will see a negative voltage...

Could someone please suggest the right/best setup for this IC and explain why this is the case? Also, could you please explain why that is the case?

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  • \$\begingroup\$ A previous question used a similar setup with apparent success. \$\endgroup\$ Commented Feb 1, 2019 at 13:10

2 Answers 2

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Just add voltage divider comprising of equal value resistors around 10k to point A, ie signal end. U re right there should be no current flow across the pot...... Connect B to ground through a cap of around 10 mfd...so AC audio signal gets grounded without current Google as Cap gets charged

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    \$\begingroup\$ Welcome to EE.SE. The CircuitLab button on the editor toolbar will enable you to create inline schematics. This would be a lot better than a textual circuit description. \$\endgroup\$
    – Transistor
    Commented Oct 24, 2018 at 16:51
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In your first circuit, install a DC-block capacitor in the output (wiper pin). On other side of capacitor, have the 10K ohm to the bias voltage.

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